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Formula and Examples of Warping Calculation

Formula and Examples of Warping Calculation
S. M. Hossen Uzzal
B.Sc. in Textile Technology
Monnu Fabrics Ltd. Manikgonj
Email: uhossen@gmail.com




Warping:
The parallel winding of warp ends from many winding packages (cone or cheese) on to a common package (warp beam) is called warping. Main purpose of warping is to arrange a convenient number of warp yarns of related length so that they can be collect on a single warper’s beam, as a continuous sheet of yarns which can be used for sizing or next process.
Warping Calculation
Formula of Warping Calculation

1. Production = Surface speed of drum × π × Dia. of drum × Creel Capacity


                                           Weight in lbs
2. The length of warp = ………………………
                                           No. of ends

               Weight of warp in lb X Count X 840
= …………………………………………………… (Yards)
                              No. of ends

              Weight of warp in lb X Count
= …………………………………………………. (Hanks)
                          No. of ends

3. The total length of yarn in the warp,

            Length of warp X No. of ends
= ……………………………………………… (Hank)
                            840

                                             Length of warp in yds X No. of ends
4. Weight of warp in lbs = ………………………………………………………
                                                          840 X Count


                                                   Count X Weight X 840
5. No of ends in the warp = …………………………………………….
                                                    Length of warp in yds


                Count X Weight in lbs
= ……………………………………………
               Length of warp in hanks


                                                              Length of warp in yds X No of ends
6. Count of warp or Beam count = ………………………………………………
                                                                        840 X Weight in lbs


                                    Total length of warp to be produced in yds
7. Time required = ………………………………………………………… hrs
                                Actual production in yds per hr X No of m/cs


8. Total length of warp to be produced in yds = Length of warp in yds required per beam X No of beams per set X No of ends

Mathematical Problem of Warping :
A super speed beam warpers with a warping speed of 840 yds per min is preparing a standard warp of 525 ends. If the yarns count 30’S and overall efficiency is 84%. Calculate the following the length of warp on each beam is required to be 44352 yds. Ignore waste.
  1. Total length of warp produced per day of 8 hrs
  2. No of beam produced per day of 8 hrs
  3. Total weight of yarn in lbs warped per drum
  4. Weight of yarn on a beam
1. Total length of warp produced per day of 8 hrs = Calculated production X Efficiency X 60

                     84
= 880 X 60 X …….. X 8 yds
                    100

= 354816 yds (ANS)

2. No of beam produced per day of 8 hrs

          Total length of warp produced per day of 8 hrs in yds
= …………………………………………………………………
                   Length of warp on a beam in yds

           354816
= …………………..
           44352

= 8 beams (ANS)

3. Total weight of yarn in lbs warped per drum

            Total length of warp yarn in yds X No of ends
= ……………………………………………………………
                               840 X Yarn count

          354816 X 525
= ………………………..
             840 X 30

= 7392 lbs. (ANS)

4. Weight of yarn on a beam

             Total weight of yarn in lb
= ……………………………………
             No of beam produced

          7342
= ………………
            8

= 924 lbs (ANS)
 

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