Subscribe For Free Updates!

We'll not spam mate! We promise.

Mathematical Formulas, Problems and Solutions of Winding

Mathematical Formulas, Problems and Solutions of Winding
 
Rana Sohel
Executive Engineer
Sunman Textile Mills Ltd. Chittagong
Cell: +8801912-420118
Email: rsohel07tex@gmail.com

 

Winding:
 
Winding is the process of transferring yarns from ring, bobbin, hank into a suitable package. It is one of the most important operation, which is mainly occurred in spinning section. Besides, it is also important in fabric manufacturing. In fabric manufacturing, directly winding is not so much important, but rewinding is so important.

Types of winding:
There are three types of winding process

  1. Parallel winding
  2. Nearly parallel winding
  3. Cross winding
Formulas of Winding:

                                     Quantity of yarn in lbs to be wound
1. Time required = …………………………………………………….
                                Actual production in lbs/hrs X No. of drums

                                                   Actual Production
2. Winding Efficiency = …………………………………………… X 100%
                                               Calculated Production

Note: Actual Production < Calculated Production

                                Calculated Production - Actual Production
3. Efficiency loss = …………………………………………………. X 100%
                                                Calculated Production


Mathematical Problems and Solutions
***How much time will be required to wind 2388 lbs of 20s cotton on 40 drums of a super speed cone winder, if the calculated of winding is 1298 yds per min and the efficiency is 80%.

Solution:

Given that,

**Quantity of yarns in lbs = 2388 lbs

**Yarn count = 20s

**No. of drums = 40

**Calculated rate of winding in minutes = 1298 yds

                                                                    1298
                                                          = …………………. Hank
                                                                     840
**Efficiency = 80%

                         80
                  = …………….
                        100


**Required time = ?

We know,

                                 Quantity of yarn in lbs to be wound
Time required = …………………………………………………….
                           Actual production in lbs/hrs X No. of drums

                                                Quantity of yarn in hank
OR, Time required = …………………………………………………………
                                   Actual production in hanks X No. of drums

                                         Quantity of yarns in lbs X Yarn count
OR, Time required = ……………………………………………………        .......(1)
                                    Actual production in hanks X No. of drums

Again we know,

Actual production per hour per drum in Hank = Calculated rate of winding in minutes X Efficiency X 60

                     80
= 1298 X …………… X 60 yds
                    100

       1298                  80
= ……………. X …………. X 60 hanks
        840                  100

= 74.17 hank

Now from (1) No. equation we get,

                                   2388 X 20
Time required = ……………………………….
                                  74.17 X 40

                        = 16.098 hrs (Ans)


If You Like Then Please Share It
SOCIALIZE IT →
FOLLOW US →
SHARE IT →

0 comments:

Post a Comment