**Some Useful Formulas for Drawing Frame**

**Md. Abu Sayed**

Founder of Textile Apex

Pabna Textile engineering college, Pabna, Bangladesh

**Email:**sayed1952@facebook.com

**Cell :**+8801745214773

**Draw Frame:**

The draw frame is the quality filter of the

**spinning**mill; errors in the draw frame sliver result inevitably in yarn defects. Hence, since quality can no longer be improved after the draw frame, the sliver quality at the last draw frame passage is of decisive importance: The slivers must be monitored in detail, metre by metre, to meet self-set quality standards. From a purely commercial view, the draw frame and drawing process is of little significance – it usually contributes less than 5% to production costs of the yarn. But from the point of view of quality of the yarn it is very much important.Draw frame |

**Essential Formula for Draw Frame**
Sliver length/Length unit

Sliver weight/Weight unit

Sliver length X Weight unit

=

Length unit X Sliver weight

Sliver length (Gauge) X 7000

=

Sliver weight (Grain) X 840

Draft constant

DCP

Front roller surface speed

=

Back roller surface speed

Front roller dia

=

Back roller dia

Feed material weight

=

Delivered material weight

= Actual draft X (100 – Waste%) /100

Delivered sliver hank X Doubling

Feed sliver hank

Feed material weight

=

Delivered material weight

Delivered material length

=

Feed material length

Total mechanical draft X 100

=

100 – Waste%

= Front roller surface speed X 60/(36 X 840 X Hank) X Eff% X Waste% (lb/hr)

For giving the clear concept, i have given some examples. You can read it clear fully.

Here given,

**1. Sliver hank**=**…………………………..**Sliver weight/Weight unit

Sliver length X Weight unit

=

**………………………………**Length unit X Sliver weight

Sliver length (Gauge) X 7000

=

**…………………………………**Sliver weight (Grain) X 840

Draft constant

**2. Technological draft**=**………………**DCP

Front roller surface speed

=

**……………………...………**Back roller surface speed

Front roller dia

=

**……………………**X Gearing from back roller to front rollerBack roller dia

Feed material weight

=

**…………………………….**X {1 – (Waste% / 100)}Delivered material weight

= Actual draft X (100 – Waste%) /100

Delivered sliver hank X Doubling

**3. Actual draft**=**……………………………………**Feed sliver hank

Feed material weight

=

**……………………………**Delivered material weight

Delivered material length

=

**……………………………**Feed material length

Total mechanical draft X 100

=

**…………………………………**100 – Waste%

**4. Delivered sliver weight**= Feed sliver weight X Doubling/Draft**Required draft**Required DCP Present hank**5.****……………………**=**………………....**=**……………………****Present draft**Present DCP Required hank**6. Production of machine**= Front roller surface speed X Eff% X Waste% (inch/min)= Front roller surface speed X 60/(36 X 840 X Hank) X Eff% X Waste% (lb/hr)

**Draw Frame Problems and Solutions:**For giving the clear concept, i have given some examples. You can read it clear fully.

**Problem-1. If any sliver hank 0.15, then what will be the weight per yard?**Here given,

- Sliver hank = 0.15
- Sliver length = 1 yard
- Sliver weight/yd =?

**Solution:**
We know,

Sliver length/Length unit

Sliver weight/Weight unit

Sliver length Weight unit

Length unit Sliver weight

Sliver length Weight unit

Length unit Sliver hank

= 1/840 X 1/0.15 = 0.0079 lb

= 0.0079 X 7000 Grain (7000 grain = 1 lb)

= 55.30 Grain

Here given,

Sliver length/Length unit

**Sliver hank**=**………………………………**Sliver weight/Weight unit

Sliver length Weight unit

**Or, Sliver hank**=**……………**X**………….……**Length unit Sliver weight

Sliver length Weight unit

**Or, Sliver weight**=**………………**X**……………………**Length unit Sliver hank

= 1/840 X 1/0.15 = 0.0079 lb

= 0.0079 X 7000 Grain (7000 grain = 1 lb)

= 55.30 Grain

**(ANS).****Problem-2. A drawing frame producing 0.18 hank sliver with DCP of 58T. If we want to produce 0.17 hank sliver, then calculate the required DCP.**Here given,

- Present DCP of drawing frame = 58
- Present hank of drawing frame = 0.18
- Required hank = 0.17
- Required DCP =?

**Solution:**
We know,

= 58 X 0.18/0.17 = 61.41 = 61T

Here given,

**Present hank**Required DCP**………………… = …………………………****Required hank**Present DCP**Or, Required DCP**= Present DCP X Present hank/Required hank= 58 X 0.18/0.17 = 61.41 = 61T

**(ANS).****Problem-3. A machine’s front roller dia is 11/10”, Sliver hank is 0.16, front roller speed is 465 r.p.m and eff.% is 90%, then what will be the production per shift of the machine?**Here given,

- Front roller dia = 11/10”
- Front roller speed = 465 r.p.m
- Sliver hank = 0.16
- Eff. of machine = 90%
- Production/shift =?

**Solution:**We know that,

**Production**= Surface speed of front roller X Eff.%

= π X Dia X Speed X Eff.%

= 3.14 X 11/10 X 465 X 90/100 inch/min

= 3.14 X 11/10 X 1/(36 X 840 X 0.16) X 465 X 60 X 8 X 90/100 lb/min

= 143.40 lb/shift

**(ANS).**

**Problem-4. To get 0.17 hank sliver from a drawing machine by feeding 0.14 hank carded sliver (No. of carded sliver is 6), calculate the required DCP. Draft constant is 234.**

Here given,

- Doubling = 6
- Feed or Carded sliver hank = 0.14
- Delivery or Drawn sliver hank = 0.17
- Draft constant of the machine = 234
- DCP =?

**Solution:**

We know,

= (0.17 X 6) / 0.14 = 1.02 / 0.14 = 7.29

Again,

**Draft**= (Deliver sliver hank X Doubling) / Feed sliver hank= (0.17 X 6) / 0.14 = 1.02 / 0.14 = 7.29

Again,

**DCP**= Draft constant/Draft = 234 / 7.29 = 32.10 = 32T**(ANS).**