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Production Calculation of Plain Circular Knitting Machine

Production Calculation of Plain Circular Knitting Machine
Raju Tex
Knitting Technologist,
B.J.Group, Mawna, Gazipur
Chittagong Textile Engineering College
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Circular Knitting Machine
All over the world, the majority of knit fabrics are manufactured on circular knitting machines. The high performance level of these machines, the different materials and the range of yarn counts that they are able to process, the wide variety of designs and stitches are some of the reasons which have granted circular machines the market leadership in the knitting sector. The variety of knit fabrics that can be manufactured with these machines can meet the needs of a very large end user market; from the traditional outwear and underwear sectors to hosiery, household and car interiors, without forgetting technical textile applications.
Plain (Single –jersey) circular knitting machine
Plain (Single –jersey) circular knitting machine
There are several types of circular knitting machine. Plain (Single –jersey) circular knitting machine is one of them. In plain circular knitting machine, an individual feeder is used for each single yarn. In this article we will discuss about production calculation of plain circular knitting machine.

Production of Plain Circular Knitting Machine:

Find out the production of machine when-
  • Machine diameter = 30”
  • Gauge,E = 28
  • Number of feeders = 96
  • Machine speed = 35 rpm
  • Machine efficiency = 85 %
  • Structure: plain(Single-jersey)
  • Yarn: cotton Nm 50/1(Ne29.6/1)
  • Course density = 18 courses/cm.
  • Wales density = 13wales/cm.
  • Fabric weight = 125gm/m2
  • Production performance = ?
We know,

                                                                                      N X S X 60 X ƞ
Machine performance L in meter per hour = ………………………………….............
                                                                        feeders/course X courses X cm X 100

      35 X 96 X 60 X 0.85
= ……………………………
          1 X 18 X 100

= 95.2 m/hr.

                                               D X π X E
Fabric width, WB in meter = ………………
                                            WPcm X 100

    30 X 3.14 X 28
= ……………………
        13 X 100

= 2.03 m

                                                             L X WB X Weight in GSM
Machine performance in Kg per hour = ………………………………
                                                                            1000

    95.2 X 2.03 X 125
= ………………………
             1000

= 24.157 Kg/hr (ANS)
 
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