Counting of Reed Count and Heald Count in Weaving
Mayedul Islam
Assistant Chemist
HaMeem Group, Tongi, Gazipur, Bangladesh
Email: mayedul.islam66@gmail.com
Assistant Chemist
HaMeem Group, Tongi, Gazipur, Bangladesh
Email: mayedul.islam66@gmail.com
Counting of reed count:
Reed determines the spacing of warp threads. Ordinary reed used for weaving cotton fabrics is made of rustless steel wires. They are bound at each end on baulks by pith bands, whose thickness determines the spacing of dents. Sometimes brass wires are used instead of rustless steel.
Required Count,
Dents Per inch in known system
= …………………………………………….. × count in known system
Dents Per inch in required system
The following two tables will be used during counting Reed & Heald count in weaving.
System based on the number of dents in a given space.
Dents Per inch in known system
= …………………………………………….. × count in known system
Dents Per inch in required system
The following two tables will be used during counting Reed & Heald count in weaving.
System based on the number of dents in a given space.
Name
of System

Basis
Of numbering

Stockport

Number
Of dents per 2 inches

Radcliff

Number
Of dents per 1 inch.

Huddersfield

Number
Of dents per 1 inch.

Metric

Number
Of dents per 1 decm.

System based on the number of groups or beers in a given space.
Name
of System

Basis
Of numbering

Bolton

20
dents per 24.5 inches.

Bradford

20
dents per 36 inches.

Blackburn

20
dents per 45 inches.

Irish

100
dents per 40 inches.

Leeds

19
dents per 9 inches.

Macclesfield

100
dents per 36 inches.

All the above systems are convertible into dents per inch basis.
Example No. 01:
Find the count of 10^{s} Irish reed into the Huddersfield System .
Solution:
10^{s} Irish,
10 × 100
= ……………
40
= 25 dents per inch.
1 Huddersfield = 1 dent per inch.
Therefore,
10^{s} Irish,
25
= ………
1
= 25^{s} Huddersfield.
So, the count in Huddersfield System is 25^{s}
Example No. 02:
Find the count of a 40^{s} Radcliff in the Stockport System.
Solution:
Count,
40 × 2
= …………..
1
= 80^{s} Stockport.
So, the count in Stockport System is 80^{s}
Example No. 03:
Find the number of ends per inch in a reed of 3/72^{s} Bradford.
Solution:
72^{s} Bradford ,
72 × 20
= ………………….. ends per inch
36
= 40 ends per inch.
Therefore, the number of ends per inch = 3 × 4
= 120 ends per inch.
Counting of heald count:
Example No. 01:
Find the count of 10^{s} Irish reed into the Huddersfield System .
Solution:
10^{s} Irish,
10 × 100
= ……………
40
= 25 dents per inch.
1 Huddersfield = 1 dent per inch.
Therefore,
10^{s} Irish,
25
= ………
1
= 25^{s} Huddersfield.
So, the count in Huddersfield System is 25^{s}
Example No. 02:
Find the count of a 40^{s} Radcliff in the Stockport System.
Solution:
Count,
40 × 2
= …………..
1
= 80^{s} Stockport.
So, the count in Stockport System is 80^{s}
Example No. 03:
Find the number of ends per inch in a reed of 3/72^{s} Bradford.
Solution:
72^{s} Bradford ,
72 × 20
= ………………….. ends per inch
36
= 40 ends per inch.
Therefore, the number of ends per inch = 3 × 4
= 120 ends per inch.
Counting of heald count:
The number of heald eyes per inch across the healds in a set expresses the count of the healds. When a set contains 4 shafts, it is called a plain set.
Example No. 04:
Find the count of the healds that will be required for weaving a 6 shaft satin fabric using 72^{s} Stockport reed, drawn 3 ends per dent.
Solution:
Number of ends per inch in the reed,
3 × 72
= ………………..
2
= 108 ends.
Therefore, rate of knitting,
108
= …………..
6
= 18 healds per inch on the rib band.
Thus we require 6 healds of 72^{s} plain set.
Example No. 04:
Find the count of the healds that will be required for weaving a 6 shaft satin fabric using 72^{s} Stockport reed, drawn 3 ends per dent.
Solution:
Number of ends per inch in the reed,
3 × 72
= ………………..
2
= 108 ends.
Therefore, rate of knitting,
108
= …………..
6
= 18 healds per inch on the rib band.
Thus we require 6 healds of 72^{s} plain set.