Subscribe For Free Updates!

We'll not spam mate! We promise.

Production Calculation of Slasher Sizing Machine

Production Calculation of Slasher Sizing Machine
S. M. Hossen Uzzal
Production Officer
Monno Fabrics Ltd., Manikgonj
Email: uhossen@gmail.com



Slasher Sizing:
Slasher sizing is the most used sizing process. In this process the warp is passed through a size liquor bath then through a separating unit and cooling unit. This method is universally adopted and is suitable for large scale operations.

Slasher Sizing Machine
Slasher Sizing Machine
Problem-1:
The calculated production of a high speed slasher is 100 yds per min. If the efficiency of the machine is 75%. Calculate

a) The actual production per day of 8 hrs.
b) The total length of yarn if the total ends is 3250 &
c) The total weight of the sized warp if it is sized to 10% & the count of the unsized yarn is 40s.

Solution:

Calculated production/day of 8 hrs = Calculated production/min in yds × 60 × 8
= 100 × 60 × 8 = 48000 yds.

a) The actual production per day of 8 hrs
= Calculated production × efficiency
= 48000 × (75/100)
= 36000 yds. (ANS)

b) Total length of the yarn sized = Total length of warp × no. of ends
= 36000 × 3250
= 117000000 yds
= 117000000/840
= 139286 hanks (ANS)

c) Weight of sized warp in lbs = (Length of the warp in hanks/Count) × 10%
= (139286/40) × 10%
= 3830 lbs (ANS)

Problem-2:
A warp containing 2800 ends is required to be sized to 25%. The length of the sized warp on the beam is required to be 1080 yds. If the count of the yarn is 40s then find –

a) The weight of the size to be put on the warp of the given length.
b) The weight of sized yarn.
c) The count of the sized warp.

Solution:

                                                             No. of ends X Required length on beam
Weight of 1080 yds of unsized warp =………………………………………….
                                                                              Count X 840

   2800 X 1080
= ……………..
    40 X 840

= 90 lbs

Therefore,

a) Weight of size to be put = 90 × Size %
= 90 × 25%
= 22.5 lbs. (ANS)

b) The weight of the sized warp =Weight of unsized warp+Weight of size on it.
= 90 + 22.5
= 112.5 lbs. (ANS)

                                              No. of ends X Required length on beam
c) The count of sized warp = …………………………………………..
                                               The weight of the sized warp X 840

    2800 X 1080
= ……………………
    112.5 X 840

= 32 's (ANS)


If You Like Then Please Share It
SOCIALIZE IT →
FOLLOW US →
SHARE IT →

1 comments:

  1. For production, we need to calculate for estimating the required amount. Here your articles playing an important role.
    Thanks.
    Visit to know about... Slasher Sizing machine

    ReplyDelete