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## Calculation of Jute Carding

Calculation of Jute Carding
Engr Avijit Dey
Production Officer
Fabian Group, Chittagong
Mobile: 01836124490
E-mail: avijitdey43@yahoo.com

Introduction:
Jute carding is a combining operation where jute reeds are splitted and extraneous matters are removed. Jute fibres are formed into ribbon called "sliver". There are three different carding sections: (i) breaker carding (ii) inner carding (iii) and finisher carding These are of a simpler nature than those required for the spreader, being confined chiefly to draft, count, and speed. The following three are typical of those met with in practice.
Problem: 1
Eight ends of 300 ktex spreader sliver are fed to a breaker with a draft constant of 500 which has a draft change pinion of 28 fitted. If the feed speed is 3m/min find the card production in an 8 hr day when it runs at 80 percent efficiency and the deliver sliver count when there is moisture and waste loss of 6 percent of the input weight. The sliver is delivered by a roll former which has a 4percent lead over the delivery rollers of the card.

Draft on the card = 500 ÷ 28 = 17.85

Delivery speed of card = 3×17.85 = 53.5m/min

Therefore, roll former delivery speed = 53.5× 1. 04 = 55.6 m/min

Daily delivery = 55.6 × 60 × 8 × 0.8 = 21400 m

300×8×0.94
Sliver count at roll former =……………………
17.85× 1. 04

= 121.5ktex

121.5×21400
Daily production = ………………………… = 2600kg (ANS).
1000

Problem: 2
It is necessary to produce breaker card sliver at a count of 18lb/100 yd.

What dollop weight must be used to meet the following conditions?

• Draft constant = 440
• Draft pinion = 30
• Feed sheet roller 7 in diameter
• Feed sheet roller 24.5 revolutions per clock revolution
• Moisture and waste loss 3.5 percent.

In a revolution of the clock the feed sheet travels,

24.5×7×3.1416yd
= …………………………………… =14.95 yd
36

That is the clock length is 14.95 yd.

Again,

Dollop × 100
= ……………………………………… = Delivery sliver (lb/100yd)
Clock length × draft

Draft = 440÷30 = 14.7

18×15×14.7
Hence, ignoring loss for the moment, Dollop weight = …………..………………
100

= 39.7 lb

To allow for losses this must be increased by 1. 035,

Correct dollop weight = 41lb (ANS).

Problem: 3
The cylinder of a finisher card rotates at180 r.p.m. Find its linear speed when its radius is24m. The feed roller travels at (1÷200) of the cylinder speed, the doffer at (1÷40) of the cylinder speed and at half the speed of the delivery rollers. Find the card draft.

180 × 2×3.1416×24
Cylinder surface speed = …………………………………
12

= 2290 ft/min.

Therefore, feed roller surface speed= 2290 ÷ 200 = 11.45ft/min

Similarly, doffer surface speed = 57.3ft/min

Therefore, delivery speed = 57.3×2 =114.6ft/min.

Machine draft = 114.6÷11.45 = 10 (ANS).

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