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Mathematical Problem of Finisher Carding Machine

Mathematical Problem of Finisher Carding Machine
Engr Avijit Dey
Production Officer
Fabian Group, Chittagong
Mobile: 01836124490
E-mail: avijitdey43@yahoo.com
 



Introduction:
Finisher card is full circular and down sticking card. After jute is processed by breaker card, it is sent to finisher card. The rollers and cylinder are pinned in the same manner as in breaker card but pins are finer and set closer together in Finisher Carding machine.


Problem 1:
Calculate the wt of sliver in lbs/100Yds delivered from the finisher card from the data:


  • B/C delivered sliver = 24 lbs/100 Yds
  • F/C draft =15
  • F/C doubling = 12
  • Waste loss = 4%
Solution:

Wt of F/C delivers sliver/Sliver delivered per 100 Yds from F/C,

                                   Doubling     100 – waste%
= B/C delivered Sliver × …………. ×………………
                                     Draft              100

          12        100 -4
= 24 ×……. × ………
          15         100

=148.432 lbs. (Ans)

Problem: 2
Calculate wt of sliver in lb/100 Yds delivered from the

F/C B/C dollop wt =32lb, B/C Clock length = 12.5 lb, B/C draft =10, F/C doubling =12, F/C draft =15.

Solution: 

                                                                  32          1
Sliver delivered per100 Yds from B/C = …….....×………. ×100
                                                                  12.5      10

= 25.6 lbs/100 


                                                     12       100-4
Sliver delivered from F/C = 25.6× …….× ……………
                                                     15        100

=19.66lbs (ANS).

Problem :3
How many ends at the feed of the finisher card are required to obtain 14.22 lb/100Yds sliver from finisher card with F/C draft=15, B/C sliver production =20lb/100Yds, M.R=3%

Solution:


Sliver delivery from F/C in lbs/100Yds,

                                                     F/C doubling     100- loses
= Delivery from B/C in lbs/100Yds ×…………….. × ………………
                                                       F/C draft            100

                         F/C doubling       100 -3
Or, 14.22 = 20×………………. × ……………..
                                15                 100


                             14.22× 15×100
Or, F/C doubling = ……………………
                                  20×97

=10.44 that means 11

11 ends will be required. (ANS)

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