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Calculation of Loom Production

Calculation of Loom Production
Rofiquzzaman Raju
Fabric Technologist,
B.J.Group, Mawna, Gazipur
Chittagong Textile Engineering College
Contact: 01714419681



What is Loom:
Loom is an apparatus/device for making fabric by weaving yarn or thread. It produces fabric by interlacing a series of length wise, parallel yarns width a series of width wise parallel yarns. To get optimum output of loom we must know about the loom production calculation. In this article I have given many examples on loom production calculation.
Loom
Production Calculation of Loom:

Problem-1:

Production of loom:

PPM = 200, PPI = 50

Production per loom per minute =200/50 =4”

Production per loom per month = 4 x 60 x 24 x 30 inch

Production per loom per year at 70% efficiency = 4 x 60 x 24 x 30 x 12 x 0.7 inch
= (4 x 60 x 24 x 30 x 12 x 0.7) / 36 yds
= (4 x 60 x 24 x 30 x 12 x 0.7) / 39.37 m
= 36868.68 m (ANS)

Problem-2:

PPM = 350
PPI = 60
No. of loom = 45
Time = 7 days
Efficiency = 90%

Find out production in m?

Solution:

                      350                                      90         1
Production = …….. x (60 x 24 x 7) x 45 x …….. x ……….. m
                      60                                       100      39.37

   14288400000
= ……………….. m
     236220

= 60487.68 m (ANS)

Problem-3:

PPM = 650
PPI = 58
No. of loom = 10
Time = 35 days
Production = 110000 m

Efficiency = ?

Solution:

                     650 x 60 x 24 x 35 x 10 x η
Production = …………………………………..
                           58 x 100 x 39.37

            110000 x 58 x 100 x 39.37
=> η = ………………………………..
             650 x 60 x 24 x 35 x 10

=> η = 76.77% (ANS)

Problem-4:

Find out Wt. of yarn in fabric (warp & weft), from the following specification.

Warp count x Weft count
.………………………...... x Fabric width
          EPI x PPI
or,

20 x 22
.………… x 56”
60 x 58

Solution:

In 5000m fabric, wt of weft warp,

    60 x 56 x 5000 x 1.05
= ……………………………………… kg
  0.914 x 840 x 20 x 2.2046

= 521.09 kg (ANS)

In 5000m fabric, wt of weft,

   58 x 39.37 x 5000 x 56 x 1.05
= ……………………………………… Kg
     36 x 840 x 22 x 2.2046

= 457.73 kg (ANS)

Problem-5:

Find out the wt. of required warp & weft to produce 5000m fabric from the following specification.

18 x 16
.………….. x 58”
66 x 62

Solution:
 
                            66 x 58 x 5000 x 1.05 x 1.1
Required warp = ………………………..……...  =  725.28 kg (ANS)
                            0.9144 x 840 x 18 x 2.0246

                           62 x 39.37 x 5000 x 58 x 1.05 x 1.1
Required weft = ………………………...................….. = 766.49 kg (ANS)
                                36 x 840 x 16 x 2.2046

Problem-6:
Calculate the yarn consumption of a loom per hour running at 180 PPM for producing from the following specification.

40 x 60
…………. x 56” fabric
72 x 48
 
Solution:

                                       180               1
Production/hour/loom = ……. X 60 x ……
                                       48                36

= 6.25 yd

                                      72 x 56 x 6.25 x 1.05 x 1.1
Req. amount of warp = …………………………………
                                            840 x 40 x 2.004

= 0.393 Kg

                                     48 x 36 x 6.25 x 56 x 1.05 x 1.1
Req. amount of weft = ……………………………………
                                          36 x 840 x 60 x 2.024

= 0.175 Kg (ANS)

Problem-7:
Calculate the time required to complete a weavers beam having 1000yds of warp on it. The woven cloth is required to have 60 PPI. Loom speed is 200 and efficiency 80%. Assume any missing data.

Solution:

                                       210      60
Production/loom/hour = ……. x ….. x 0.8
                                       60        36

= 4.67yds

                   Length of cloth from the beam
Time req. = …………………………………
                       Actual production/hr

Length of cloth from the beam,

                                      100 – crimp
= (Length in yds of warp x …………….) – Waste in yards
                                           100

               100 – 6
= (1000 x …………) – 6
                 100

= 934 yds

                                 934
So, Time required = ……….
                                 4.67

= 200hr (ANS)

Problem-8:
Calculate the actual yarn consumption per month of weaving mil having 100 looms of 250 ppm for the following fabric construction. Considering each point.

80 x 60
…………. X 56”
110 x 54

Production per month of 100 looms at 100% efficiency,

   250                                100
= …….. x (60 x 24 x 30) x …….
    54                                  36

= 555556 yds

                                           110 x 56 x 555556 x 1.05 x 1.1
Required amount of warp = …………………………………
                                                     840 x 80 x 2.204

= 26687 Kg

                                            54 x 36 x 555556 x 56 x 1.05 x 1.1
Required amount of weft = …………….....……………...……..
                                                     36 x 840 x 60 x 2.204

= 17468 Kg (ANS)

Problem-9:
Find out thrust in Newton to drive a loom by using plate clutch system and conical clutch system. If F=425N, μ=0.45 and θ=20°

Solution:

                                   F           425
For plate clutch, P = …….. = ………. = 944.44 Newton
                                  µ            0.45

                                                 F sin θ     425 sin 200
For conical clutch system, P = ………. = …………… = 323.02 Newton (ANS)
                                                    µ               0.45

Problem-10:
Calculate the production per shift of 10 hrs at 90% efficiency a weaving mill in average 22 picks per cm from the following information:

No. of looms .........picks/cm .........PPM
120 ........................20 ...................220
16 ..........................25 ....................210
110 ....................... 28 ................... 200

                                              220                       90                1
Production at 22 picks/cm = …… x (60 x 10) x …….. x 120 x ……. M
                                               20                       100              100

= 6480 m

                                             220                      90             1
Production at 22 picks/cm = …… x (60 x 10) x ….. x 16 x …….
                                              20                      100           100

= 824.73 m

                                            220                      90               1
Production at 22 picks/cm = …… x (60 x 10) x ….. x 110 x …….
                                             20                      100             100

= 5400 m

Average production = (6480 + 824.734+5400) m

= 12704.73 m (ANS)

Problem-11:

Calculate the “speed space” required to produce a elastic fabric having 30% shrinkage (width of finished fabric 50″)
                                                    130
Required reed space = 11 x 50 x ……
                                                    100

= 65 inch (ANS)

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