**Beam Count Calculation in Warping**

**Amit Kumar Das**

Founder of "টেক্সটাইল ম্যানিয়া" Blog

Pabna Textile engineering college, Pabna, Bangladesh

**Cell:**01770 456240

**Email:**amitptec6th@gmail.com

**Introduction:**

Yarn is wound onto a perforated warp beam for

**weaving**preparation. It is used as a package for yarn when fabrics are to be woven. In using this, its essential to know the count of this yarn package. We know one count is defined as a bundle of 840 yards. Weights 1 pound (lb). For determining the count of warp beam we can use same theory that has been written in previous post.

Yarn warping on beam |

**For your help this will be discussed one again.**1 pound = 7000 grains

1 penny weight(dwt.) = 24 grains

1 lea equals = 120 yards

From the above a lea of 1 s count weight is 1000 grains.

If 1000 grains is the lea weight the count is 1s

And If 50 grains is the lea weight the count is 1000/50 =30s

And If 25 grains is the lea weight the count is 1000/25 =40s

And so on.

This method of calculation can be extended to determine the beam counts in weaving preparatory like beam count .

**Some things need to be noted:**As beam counts are a useful check on the spinning correct wrapping, every care to be taken at the warping stage to see that

- The beam tare weight is correct.
- The total ends in creel are correct and ectra.
- The length on beam initially is also accounted before the yardage dial is reset.
- The beam weighment scale is accurate.

**Mathematical Problem and Solution:**

**Problem: 01**

A wrapper’s beam containing 420 ends and a length of 2000 yards weights(net) 20 pounds. Find the beam count ?

**Solution:**Total continuous length of 420 ends = (2000 x 420) yards

So one lea (120 yards) weight = { (20 x 7000 x 120) ÷ (2000 x 420)grains }

= 20 grains

**Hence beam count**= 1000/20

= 50s

**(ANS.)**

**Problem: 02**

One lea of yarn is wrapped from each of four bobbins and the total wrappings are found to weight 4 dwt. 8 grs. Find out the

**count of yarn**?

**S**

**olution:**Weight of 4 leas in grains = 104

**So yarn count**= { (4 x 1000) ÷ 104 } = 38.4s (ANS.)

**Problem: 03**

A bundle of 264 yards of a certain yarn weights 1 dwt. 3.5 grs. Then what will be the count?

**Solution:**Bundle weight = 1 dwt. 3.5 grs. = 27.5 grains

27.5 grains is the weight of = 264 yards

**So 7000 grains is the weight of**= [ (264 x 7000) ÷ 27.5 ]

= 80s

**(ANS.)**

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