Beam Count Calculation in Warping
Amit Kumar Das
Founder of "টেক্সটাইল ম্যানিয়া" Blog
Pabna Textile engineering college, Pabna, Bangladesh
Cell: 01770 456240
Email: amitptec6th@gmail.com
Amit Kumar Das
Founder of "টেক্সটাইল ম্যানিয়া" Blog
Pabna Textile engineering college, Pabna, Bangladesh
Cell: 01770 456240
Email: amitptec6th@gmail.com
Introduction:
Yarn is wound onto a perforated warp beam for weaving preparation. It is used as a package for yarn when fabrics are to be woven. In using this, its essential to know the count of this yarn package. We know one count is defined as a bundle of 840 yards. Weights 1 pound (lb). For determining the count of warp beam we can use same theory that has been written in previous post.
Yarn is wound onto a perforated warp beam for weaving preparation. It is used as a package for yarn when fabrics are to be woven. In using this, its essential to know the count of this yarn package. We know one count is defined as a bundle of 840 yards. Weights 1 pound (lb). For determining the count of warp beam we can use same theory that has been written in previous post.
Yarn warping on beam |
1 pound = 7000 grains
1 penny weight(dwt.) = 24 grains
1 lea equals = 120 yards
From the above a lea of 1 s count weight is 1000 grains.
If 1000 grains is the lea weight the count is 1s
And If 50 grains is the lea weight the count is 1000/50 =30s
And If 25 grains is the lea weight the count is 1000/25 =40s
And so on.
This method of calculation can be extended to determine the beam counts in weaving preparatory like beam count .
Some things need to be noted:
As beam counts are a useful check on the spinning correct wrapping, every care to be taken at the warping stage to see that
- The beam tare weight is correct.
- The total ends in creel are correct and ectra.
- The length on beam initially is also accounted before the yardage dial is reset.
- The beam weighment scale is accurate.
Problem: 01
A wrapper’s beam containing 420 ends and a length of 2000 yards weights(net) 20 pounds. Find the beam count ?
Solution:
Total continuous length of 420 ends = (2000 x 420) yards
So one lea (120 yards) weight = { (20 x 7000 x 120) ÷ (2000 x 420)grains }
= 20 grains
Hence beam count = 1000/20
= 50s (ANS.)
Problem: 02
One lea of yarn is wrapped from each of four bobbins and the total wrappings are found to weight 4 dwt. 8 grs. Find out the count of yarn?
Solution:
Weight of 4 leas in grains = 104
So yarn count = { (4 x 1000) ÷ 104 } = 38.4s (ANS.)
Problem: 03
A bundle of 264 yards of a certain yarn weights 1 dwt. 3.5 grs. Then what will be the count?
Solution:
Bundle weight = 1 dwt. 3.5 grs. = 27.5 grains
27.5 grains is the weight of = 264 yards
So 7000 grains is the weight of = [ (264 x 7000) ÷ 27.5 ]
= 80s (ANS.)