**Important Calculation of Carding**

**Carding:**

**Carding**is a mechanical process that breaks up, cleans and intermixes fibers to produce a continuous web or sliver suitable for subsequent processing. Carding is one of the most important operations in the spinning process. It is called heart of spinning. In this article I have given various problems and solutions of carding. Before reading this article you should follow the

**formulas of carding operation**.

Carding section |

**Important Calculation of Carding:**

**Problem-1:**

Calculate the cleaning efficiency of carding from following data:

Trash in lap = 6.5 lbs

Trash in sliver = 1.5 lbs

**Solution:**Trash in lap - Trash in sliver

**Cleaning efficiency of carding = ……………………………….**X 100

Trash in lap

6.5 -1.5

=

**……….**X 100

6.5

= 76.9% = 77%

**(Ans).**

**Problem-2:**

In a carding m/c D.C.P is 20 & draft constant is 2220. Find the draft of the m/c.

**Solution:**We know,

Draft constant

**Draft = …………..…………**

Draft change pinion

2220

=

**………**

20

= 111.

**(Ans.)**

**Problem-3:**

Find the required D.C.P from the following information-

Present D.C.P = 21T

Present Hank = 14 Reqd Hank = 18.

**Solution:**We know,

Present hank

**Required D.C.P**= Present D.C.P x

**…………………**

Required Hank

0.18

= 58 x

**……….**

0.16

= 65 T

**(ANS)**

**Problem-4:**

Calculate the production/hr in kg of 10 carding m/cs from the following informations –

- Doffer r.p.m = 45,
- Doffer dia = 27 inch,
- Hank of sliver = 0.15s Ne,
- Waste extraction = 4% &
- Efficiency = 90%.

**Solution:**π x 45 x 27 x 60 x 90 x (100 - 4)

Production / hr =

**…………………………......................…..**lb

840 x 36 x100 x100 x 0.15

= 43.60 lbs.

= 19.78 kg. [1 kg = 2.204 lbs]

**Production/hr of 10 carding m/c**= 19.78 x10 = 197.8 kg.

**(Ans.)**

**Problem-5:**

Feed roller dia = 2.25 inch, Feed roller r.p.m = 4, Doffer dia = 27 inch, Doffer r.p.m = 30, Lap wt = 14 os/yd, Carding eff. = 90%. Find the prodn/hr in lbs.

__Solution:__1yd x1lb

**Lap hank = ..............................**

840yds x (14/16)

= 1.36 x 10

^{-3}

Surface speed of delivery roller

**Draft = ..............................................................**

Surface speed of feed roller

π x 27 x 30

=

**…………………**

π x 2.25 x 4

= 90

We know,

delivery hank

**Draft = ………………**

feed hank

**Delivery hank**= 90 x1.36 x10

^{-3}= 0.1224.

We know,

π x D x N x 60 x 90

**Production / hr**=

**……………………….........**lb

840 x 36 x 0.1224 x100

3.14 x 27 x 30 x 60 x 90

=

**………………………………..**lb

840 x 36 x 0.1224 x100

= 37.11 lbs.

**(Ans.)**

**Problem-6:**

The surface speed of the coiler wender rollers calculated & found to be 39.1 m/min. If the linear density of the sliver is 4 kilo Tex (4kg/km). What is the production per hr at 80% efficiency.

**Solution:**Production = πDN x Efficiency

80

= 39.1 x

**………**m/min

100

80 4

= 39.1 x

**………**x

**………**x 60 kg/hr

100 1000

= 7.50kg / hr

**(Ans.)**

**Problem-7:**

Here, doffer r.p.m = 1, Dia = 27 inch, sliver wt = 1grain/yds. Tension draft = 1. Find the production constant at 85% eff.

**Solution:**

πDN x 60 x eff .x sliver wt./grain x tension draft

**Production constant = ……………………………............................……….**

36 x 100 x 7000

= 0.017

**(ANS)**

**Problem-8:**

Calculate the production in card from the following details – Doffer r.p.m = 9.95, sliver wt 50 grains/yd, prodn const. 0.017, tension draft 1.03, efficiency 85%

**Solution:****Production**= Production constant x doffer r.p.m x T.D x sliver wt. gr/yd

= 0.017 x 9.95 x1.03 x 50

= 8.71 lbs.

**(Ans.)**

**Problem-9:**

Feed mtl wt. (lap wt) = 14 oz/yd, total draft of m/c = 105, doffer speed = 30, dia = 27 inch, eff. 85%. Calculate prodn in lb/hr.

**Solution:**

1x1

**Lap hank = .........................**

840 x 14/16

**Feed hank**= 1.36 x10

^{-3}

**Draft hank**= draft x feed hank

= 105 x 1.36 x10

^{-3}

= 0.1428

3.14 x 30 x 27 x 60 x 85

**Production/hr**=

**………………………..…......**

840 x 36 x 0.1428 x100

= 30.04 lbs

**(Ans.)**

**Problem-10:**

Find the total prodn of a carding m/c for 1 hr with following details: doffer r.p.m = 10, dia = 27 inch, sliver hank = 0.15, eff. =90%.

__Solution:__π x D x N x eff .x 60

**Production/hr = ………………..………**

lbs 36 x 840 x count

3.14 x 27 x10 x 60 x 90 x 1

=

**…………………………………**

36 x 840 x100 x 0.15

= 10.098 lbs

**(Ans.)**

**Problem-11:**

Find the prodn of a carding m/c for 8hrs with the help of following data: c. roller r.p.m = 80, dia = 4 inch, sliver hank =.14, eff. = 85%, tension draft =1.05

**Solution:**3.14 x 80 x 4 x 0.85 x 60 x 8

**Production = ………………………………….**

36

= 11393.536 yds/8hrs

**Production of Coiler Calender roller**= 11393.536 x1.05 yds/8hrs.

= 11963.213 yds/8hrs.

1

**Production of carding machine**= 11963.213 x

**………......….**lb/8hrs

3.14 x 840

= 101.72799 lbs/8hrs.

**(Ans.)**

**Problem-12:**

In a carding m/c it produce sliver wt. of 60 gr/yds when its DCP is 17. To produce sliver wt. of 70 gr/yds then how many teeth of D.C.P should be used?

**Solution:**Present D.C.P. x Required wt of sliver

**Required D.C.P. = ……………………………............……..**

Present wt. of sliver

90

= 17 x

**……**

60

= 25.5

= 26

**(ANS)**

**Problem-13:**

The present produced sliver hank of a carding m/c is 0.16. Present D.C.P 18T. If reqd DCP is 22T, then calculate the sliver hank (required).

**Solution:**Present D.C.P.

**Required sliver hank**= Present sliver hank x

**………………….**

Required D.C.P

18

= 0.16 x

**…...**

22

= 0.130

**(Ans.)**

Very good post, that's help my works. Thanks.

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