**Production Calculation of Speed Frame or Simplex**

**Rofiquzzaman Raju**

Fabric Technologist,

B.J.Group, Mawna, Gazipur

Chittagong Textile Engineering College

**Facebook:**https://www.facebook.com/ERZRAZU

**Speed Frame:**

Speed
Frame or Simplex is an important process in ring spinning. In this
process fibers are converted into low twist lea called roving. So it is
also called roving frame. The main function of roving frame is the
attenuation of sliver. To draft the sliver to reduce weight per unit
length. The sliver which is taken from draw frame is thicker so it is
not suitable for manufacturing of yarn. By speed frame sliver are
converted to roving. Which is appropriate for next process. Speed frame
is used to the carded and

**combed yarn**process but for the rotor**spinning**system this process can be eliminated.**Simplex Production Calculation:**

**Problem: 1**

Calculate the TPI (twist per inch) produced on a simplex with diameter of front roller 28 mm and its rpm be 30. The rpm of flyer is 1000.

**Solution:**

Here,

Dia of front roller = 28 mm = 2.8 cm = 1.1024 inch

rpm of front roller = 30

rpm of flyer = 1000

TPI = ?

We know,

**Surface speed of front roller**= π x Dia of front roller x rpm of front roller

= π x 1.1024 x 30

= 103.9 inch/min

Flyer speed or Spindle speed (rpm)

**Twist or TPI = ………………......……………………**

Delivery speed (inches/min)

1000

=

**……………**

103.9

= 9.63

**(Ans)**

**Problem: 2**

Calculate the TPI on simplex if the diameter of back roller is 15/16’’, rpm of B.R is 10, rpm of flyer is 1000 and draft is 6.

**Solution:**

Here,

Dia of B.R. = 15/16 = 0.9375 inch

Draft = 6

rpm of F.R. = 30

rpm of B.R = 10

rpm of flyer = 1000

TPI = ?

We know,

**Surface speed of B.R.**= π x Dia of B.R. x rpm of B.R

= π x 0.9375 x 10

= 29.45 inch/min

Surface speed of F.R.

**Total draft = ………………………….**

Surface speed of B.R.

=> Surface speed of F.R.= 6 x 29.45 = 176.7 inch/min

Flyer speed or Spindle speed (rpm)

**Twist or TPI = …………………......……………….**

Delivery speed (inches/min)

1000

=

**…………**

176.7

= 5.66

**(Ans)**

**Problem: 3**

If Spindle speed = 1600 rpm, Roving count = 90 Ne, TM (Twist Multiplier) = 4.2, Efficiency = 85% then calculate the production of a speed frame in lb/hr.

**Solution:**

We know,

Spindle speed

**Production = ……………..**

TPI

**TPI**= TM√(Roving

**count**)

**Efficiency**= 85% = 85/100 = 0.85

Now,

Spindle speed

**Production = ……………..**

TPI

1600 x 60 x 1 x 0.85 x 120

**= ……………………………………….**

4.2√.90 x 36 x 840 x 0.90

= 90.297

**(Ans)**

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