# Textile Calculation

Problems and solutions of textile

## Formula and Examples of Warping Calculation

Formula and Examples of Warping Calculation
S. M. Hossen Uzzal
B.Sc. in Textile Technology
Monnu Fabrics Ltd. Manikgonj
Email: uhossen@gmail.com

Warping:
The parallel winding of warp ends from many winding packages (cone or cheese) on to a common package (warp beam) is called warping. Main purpose of warping is to arrange a convenient number of warp yarns of related length so that they can be collect on a single warper’s beam, as a continuous sheet of yarns which can be used for sizing or next process. Formula of Warping Calculation

1. Production = Surface speed of drum × π × Dia. of drum × Creel Capacity

Weight in lbs
2. The length of warp = ………………………
No. of ends

Weight of warp in lb X Count X 840
= …………………………………………………… (Yards)
No. of ends

Weight of warp in lb X Count
= …………………………………………………. (Hanks)
No. of ends

3. The total length of yarn in the warp,

Length of warp X No. of ends
= ……………………………………………… (Hank)
840

Length of warp in yds X No. of ends
4. Weight of warp in lbs = ………………………………………………………
840 X Count

Count X Weight X 840
5. No of ends in the warp = …………………………………………….
Length of warp in yds

Count X Weight in lbs
= ……………………………………………
Length of warp in hanks

Length of warp in yds X No of ends
6. Count of warp or Beam count = ………………………………………………
840 X Weight in lbs

Total length of warp to be produced in yds
7. Time required = ………………………………………………………… hrs
Actual production in yds per hr X No of m/cs

8. Total length of warp to be produced in yds = Length of warp in yds required per beam X No of beams per set X No of ends

Mathematical Problem of Warping :
A super speed beam warpers with a warping speed of 840 yds per min is preparing a standard warp of 525 ends. If the yarns count 30’S and overall efficiency is 84%. Calculate the following the length of warp on each beam is required to be 44352 yds. Ignore waste.
1. Total length of warp produced per day of 8 hrs
2. No of beam produced per day of 8 hrs
3. Total weight of yarn in lbs warped per drum
4. Weight of yarn on a beam
1. Total length of warp produced per day of 8 hrs = Calculated production X Efficiency X 60

84
= 880 X 60 X …….. X 8 yds
100

= 354816 yds (ANS)

2. No of beam produced per day of 8 hrs

Total length of warp produced per day of 8 hrs in yds
= …………………………………………………………………
Length of warp on a beam in yds

354816
= …………………..
44352

= 8 beams (ANS)

3. Total weight of yarn in lbs warped per drum

Total length of warp yarn in yds X No of ends
= ……………………………………………………………
840 X Yarn count

354816 X 525
= ………………………..
840 X 30

= 7392 lbs. (ANS)

4. Weight of yarn on a beam

Total weight of yarn in lb
= ……………………………………
No of beam produced

7342
= ………………
8

= 924 lbs (ANS)