# Textile Calculation

Problems and solutions of textile

## Find Out the Production of Jacquard Circular Knitting Machine

Find Out the Production of Jacquard Circular Knitting Machine
Raju Tex
Knitting Technologist,
B.J.Group, Mawna, Gazipur
Chittagong Textile Engineering College

Jacquard circular knitting machine
A jacquard circular knitting machine is disclosed provided with a needle cylinder driving mechanism capable of optionally and readily controlling the rotary motion of the needle cylinder according to the pattern to be knitted.
 Jacquard circular knitting machine
A two-color jacquard fabric is to be produced, and the following machine and fabric data were assumed:

Example-1:

Values of circular knitting machine:
• Machine diameter = 26”
• Gauge E = 20
• Number of feeders = 60
• Machine speed = 27rpm
• Machine efficiency = 80%
Values of article:
• Structure: two colour jacquard (two part
• Courses for one course)
• Yarn: cotton yarn Nm = 50/1(80%), polyester filament yarn dtex = 67f14(20%)
• Course density = 10.5courses/cm.
• Wales density = 16wales/cm.
• Fabric weight = 90gm/m2
We know that,

n X S X 60 X ŋ
Machine performance L in meter per hour = ………………………………………..
feeders/course X courses/cm X 100

27 X 60 X 60 X 0.80
= …………………………
2 X 10.5 X l00

= 37 m/hr.

D X π X E
Fabric width, WB in meter = …………………
wpcm X 100

26 X 3.14 X 20
= ……………………
16 X 100

= 1.02m

L X WB X Weight in GSM
Machine performance in Kg per hour = ……………………………
1000

37 X 1.02 X 90
= …………………
1000

= 3.396 Kg/hr

Example-2:
Values of circular knitting machine:
• Machine diameter = 30”
• Gauge E = 20
• Number of feeders = 96
• Machine speed = 23rpm
• Machine efficiency = 80%
Values of article:
• Structure: three colour jacquard
• Yarn: polyester dtex = 150/1
• Course density = 12courses/cm.
• Wales density = 11wales/cm.
• Fabric weight = 180gm/m2
n X S X 60 X ŋ
Machine performance L in meter per hour = ………………………………………..
feeders/course X courses/cm X 100

23 X 96 X 60 X 0.80
= ……………………………
3 X 12 X 100

= 29.44 m/hr.

D X π X E
Fabric width, WB in meter = …………………
wpcm X 100

30 X 3.14 X 20
= ……………………
11 X l00

= 1.7m

L X WB X Weight in GSM
Machine performance in Kg per hour = ……………………………
1000

29.44 X 1.7 X 18
= ……………………
1000

= 9 Kg/h

Example-3:
Calculate the production of a single-jersey circular knitting machine in kg/hr from the following data:

Values of circular knitting machine:

• Machine diameter = 30”
• Gauge E = 28
• Number of feeders = 96
• Machine speed = 35rpm
• Machine efficiency = 80%
Values of article:
• Structure: plain(Single jersey)
• Yarn: cotton Nm 50/1(Ne29.6/1)
• Stitch length = 0.25cm
n X S X(π X d X E X stitch length in cm)X 60 X ŋ X 0.4536
= …………………………………………………………………………
100 x l00 X Ne x 840 x 0.9144

n X S X(d X E X stitch length in cm.) X ŋ
= ……………………………………...........…… X 0.00001112598
Ne

35 X 96 x (30 X 28 X 0.25) X 80
= ……………………………….....…. X 0.00001112598
29.6

=21.22 Kg. (ANS)